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Ba Cut (1923–1956) was a military commander of the Hòa Hảo religious sect, which operated from the Mekong Delta and controlled various parts of southern Vietnam during the 1940s and early 1950s. Ba Cụt and his forces fought the Vietnamese National Army, the Việt Minh, and the Cao Đài religious movement from 1943 until his capture in 1956. Known for his idiosyncrasies, he was regarded as an erratic and cruel leader who fought with little ideological purpose. His sobriquet came from the self-amputation of a finger as part of a vow during his teenage years to defeat the French colonial forces; he later swore not to cut his hair until the communist Việt Minh were defeated. Ba Cụt frequently made alliances with various Vietnamese factions and the French. He invariably accepted the material support offered in return for his cooperation, and then broke the agreement—nevertheless, the French made deals with him on five occasions. In mid-1955, the tide turned against the various sects, as Prime Minister Ngô Đình Diệm of the State of Vietnam and his VNA began to consolidate their grip on the south. Ba Cụt and his allies were driven into the jungle, and their position was threatened by government offensives. After almost a year of fighting, Ba Cụt was captured. He was sentenced to death and publicly beheaded in Cần Thơ. (more...) Recently featured: The Disasters of War – United States Academic Decathlon – Wulfhere of Mercia Archive – By email – More featured articles...From Wikipedia under the
GNU Free Documentation License What is the probability of having a snow day tomorrow (best guess)? Q. What is the probability of having a snow day tomorrow (best guess)? 2W0&metric=1&poptype=snow #accupop what do you think? maybe? thankyouu. Asked by Jasper M - Tue Dec 8 21:00:15 2009 - - 1 Answers - 0 Comments A. Cant tell, the link doesnt work- what city are you near in canada? Answered by allukcatsbaby - Tue Dec 8 21:54:23 2009 how do i solve this resonance in undamped differential equation.? Q. how do i get it from: y'' + w0^2 y = A cos(wt) to: w != w0 y(t) = [2A/ (w0^2 - w^2)] sin(w0-w/2)sin(w0+w/2) and w=w0 y(t) = A/2w0 * t sin(w0*t) Asked by luigi m - Wed Nov 26 01:22:58 2008 - - 1 Answers - 0 Comments A. your 1st y(t) is not valid as it has no variable...you certainly know that the homogeneous solution is c1 cos (w0 t) + c2 sin (w0 t)...to solve in the first case you need to find a & b so that a cos (wt) + b sin(wt) is a solution...{ b = 0 & a = A / [ (w0) - w ] }, in the 2nd case you try "a t cos (wt) + b t sin (wt)" and find values for a & b { a = 0 & b = A / 2w...w = w0 here}...try it , it does not take long Answered by ted s - Thu Nov 27 23:58:47 2008 Anyone with a North Face jacket know what size would work for me?
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